ASP.NET实现微信抢红包代码实例

正文

100块发30个红包

50块发13个红包

1块发10个红包

发红包需要满足以下几个条件

1.总金额不变
2.每个红包都必须有钱
3.尽量的均匀点,不然抢红包没什么意思了

实现思路
1.首先要确定最小单位,这里是精确到分,我这里以int类型进行计算,得出的结果也全是int类型
2.数据均匀,这里以 1<n<(剩余金额/剩余红包数)*2,这里防止一个红包抢走大量的钱,这里需要写个递归,去检查数据值是否过大,50元发13个红包的第3图,就是因为没有检查数据,导致钱不平均,这个可以根据自己的玩法去设置.
3.余数处理,当数据平均给20个红包,肯定跟总金额有所偏差,这时候我们就要多退少补,如果大于总金额,让红包金额多的去减少(总金额/总人数),如果还有剩余,就让第二多的去减少,直到补完这个空缺为止,反之亦然.
4.打乱顺序,细心的园友可能发现,红包是有顺序规律的,我们必须简单的写个function去打乱它.　　

demo

/// <summary> /// 抢红包 /// </summary> /// <param name="money"></param> /// <param name="num"></param> /// <returns></returns> public List<int> qhb(int money, int num) {  int min = 1;  int pjs = money / num;  List<int> list = new List<int>();  Random rnd = new Random();  for (int i = 0; i < num; i++)  {  int max = (money / (num - i)) * 2;  int s = rnd.Next(min, max);  s = checkmoney(s, min, max);  list.Add(s);  money -= s;  }  //前面数据都是合理的,结尾必须多退少补  list = checklist(money, pjs, list);  return list; }

/// <summary> /// 余数处理 /// </summary> /// <param name="money"></param> /// <param name="list"></param> /// <returns></returns> public List<int> checklist(int money, int pjs, List<int> list) {  if (money != 0)  {  if (money > 0)  {   List<int> list_order = maopao(list);   //给最小   if (money / pjs == 0)   {      list_order[0] += money;   }   else   {   for (int i = 0; i < money / pjs + 1; i++)   {    if (i == money / pjs)    {    list_order[i] += (money - (money / pjs) * pjs);    }    else    {    list_order[i] += pjs;    }   }   }   return list_order;  }  else  {   List<int> list_order = maopao(list,"desc");   //给最大   if (money / pjs == 0)   {   list_order[0] += money;   }   else   {   for (int i = 0; i < -(money / pjs) + 1; i++)   {    if (i == -(money / pjs))    {    list_order[i] += (money - (money / pjs) * pjs);    }    else    {    list_order[i] -= pjs;    }   }   }   return list_order;  }  }  return list; }

 /// <summary>  /// 冒泡排序  /// </summary>  /// <param name="list"></param>  /// <param name="order"></param>  /// <returns></returns>  public List<int> maopao(List<int> list,string order = "asc")  {  if (order != "asc")  {   for (int i = 0; i < list.Count; i++)   {   for (int j = 0; j < list.Count - i - 1; j++)   {    if (list[j + 1] > list[j])   {    int temp = list[j];    list[j] = list[j + 1];    list[j + 1] = temp;     }   }   }  }  else   {   for (int i = 0; i < list.Count; i++)   {   for (int j = 0; j < list.Count-i-1;j++)   {    if (list[j+1] < list[j])    {    int temp = list[j];    list[j] = list[j+1];    list[j+1] = temp;   }   }  }  }  return list; }

/// <summary> /// 打乱顺序  /// </summary>  /// <param name="list"></param>  /// <returns></returns> public List<int> suiji(List<int> list)   {  Random rnd = new Random();  for (int i = 0; i < list.Count; i++)  {   int temp = list[i];   int j = rnd.Next(0, list.Count-1);   list[i] = list[j];   list[j] = temp;  }  return list; }

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